Question

How do you find the axis of symmetry and vertex point of the function: `y=2x^2+6x+4`?

Answer 1

Find vertex of `y = 2x^2 + 6x + 4`

Explanation:

x-coordinate of axis of symmetry and of vertex:
`x = (-b/2a) = -6/4 = -3/2`
y-coordinate of vertex:
`y = f(-3/2) = 2(9/4) + 6(-3/2) + 4 = 18/4 - 18/2 + 4 = -2/4 = -1/2`
graph{2x^2 + 6x + 4 [-5, 5, -2.5, 2.5]}