# How do you find the axis of symmetry and vertex point of the function: # y = -x^2 + 6x + 2#?

##### 1 Answer

Jan 26, 2018

#### Explanation:

#"given the equation in "color(blue)"standard form"#

#•color(white)(x)y=ax^2+bx+c color(white)(x);a!=0#

#"then the x-coordinate of the vertex which is also "#

#"the axis of symmetry is"#

#x_(color(red)"vertex")=-b/(2a)#

#y=-x^2+6x+2" is in standard form"#

#"with "a=-1,b=6" and "c=2#

#rArrx_(color(red)"vertex")=-6/(-2)=3#

#"substitute this value into the equation for y"#

#rArry_(color(red)"vertex")=-(3)^2+6(3)+2=11#

#rArrcolor(magenta)"vertex "=(3,11)#

#"and axis of symmetry is "x=3#