Question

How do you find the axis of symmetry and vertex point of the function: `y = x^2 + x + 3`?

Answer 1

Find vertex of `y = x^2 + x + 3`

Ans: `(-1/2, 11/4)`

Explanation:

x-coordinate of vertex and axis of symmetry:
`x = (-b/(2a)) = - 1/2`
y-coordinate of vertex
`y = y(- 1/2) = 1/4 - 1/2 + 3 = 11/4`
`Vertex (-1/2, 11/4)`