# How do you find the axis of symmetry and vertex point of the function: y = x^2 + x + 3?

Oct 8, 2015

Find vertex of $y = {x}^{2} + x + 3$

Ans: $\left(- \frac{1}{2} , \frac{11}{4}\right)$

#### Explanation:

x-coordinate of vertex and axis of symmetry:
$x = \left(- \frac{b}{2 a}\right) = - \frac{1}{2}$
y-coordinate of vertex
$y = y \left(- \frac{1}{2}\right) = \frac{1}{4} - \frac{1}{2} + 3 = \frac{11}{4}$
$V e r t e x \left(- \frac{1}{2} , \frac{11}{4}\right)$