Question

How do you find the axis of symmetry, graph and find the maximum or minimum value of the function `y= 2(x-3)^2`?

Answer 1

Axis of symmetry is `x=3` and the minimum point is vertex `(3,0)`

Explanation:

Comparing with the general form `y=a(x-h)^2+k` here `h=3 , k=0 ,a=2` The vertex is at (h.k) i.e `(3,0)` ; Axis of symmetry is `x=3` The parabola opens up as `a` is positive. So the minimum point is vertex `(3,0)` graph{2(x-3)^2 [-10, 10, -5, 5]}