# How do you find the axis of symmetry, graph and find the maximum or minimum value of the function y= 2(x-3)^2?

Axis of symmetry is $x = 3$ and the minimum point is vertex $\left(3 , 0\right)$
Comparing with the general form $y = a {\left(x - h\right)}^{2} + k$ here $h = 3 , k = 0 , a = 2$ The vertex is at (h.k) i.e $\left(3 , 0\right)$ ; Axis of symmetry is $x = 3$ The parabola opens up as $a$ is positive. So the minimum point is vertex $\left(3 , 0\right)$ graph{2(x-3)^2 [-10, 10, -5, 5]}