# How do you find the axis of symmetry, vertex and x intercepts for #y=-x^2-2x#?

##### 1 Answer

Axis of sym at

#### Explanation:

Let's find the axis of symmetry first, it is an easy way to find the vertex.

The vertex lies on the axis of symmetry:

If

**Intercepts:**

For y-int:

For x-intercepts :

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Using the completing the square method to find the vertex:

Confirm these points on the graph below.

graph{-x^2-2x [-3.5, 1.5, -1.4, 1.1]}