# How do you find the axis of symmetry, vertex and x intercepts for #y=x^2-4x#?

##### 2 Answers

Axis of symmetry = 2

Vertex = (2,-4)

X-intercepts = 0,4

#### Explanation:

The axis a symmetry can be found using a simple formula of

when the graph is in the form of

In your graph,

Additionally, the vertex also resides on the axis of symmetry. We just need to find the y-coordinate of the vertex, which we can do by substituting

Thus, the vertex will lie on

To find the x-intercepts, we must find where the graph intersects the x-axis and this can be done when we let the graph equal zero.

Factorising we get

Finally, using the null factor law, we can find what the x-intercepts are.

**Vertex is at** **axis of symmetry is** **and**

**intercepts are**

#### Explanation:

Standard vertex fom of equation

vertex we find here

Axis of symmetry is

Vertex is at

graph{x^2-4x [-10, 10, -5, 5]} [Ans]