How do you find the center and diameter of ( x+6 )^2 + ( y-15 )^2=9?
1 Answer
Apr 16, 2018
Explanation:
#"the equation of a circle in standard form is "#
#color(red)(bar(ul(|color(white)(2/2)color(black)((x-a)^2+(y-b)^2=r^2)color(white)(2/2)|)))#
#"where "(a,b)" are the coordinates of the centre and r is"#
#"the radius"#
#(x+6)^2+(y-15)^2=9" is in standard form"#
#"with "(a,b)=(-6,15)" and "r^2=9rArrr=3#
#rArr"centre "=(-6,15)#
#"and diameter "=2r=2xx3=6#