How do you find the center and diameter of ( x+6 )^2 + ( y-15 )^2=9?

1 Answer
Apr 16, 2018

#"centre "=(-6,15),"diameter "=6#

Explanation:

#"the equation of a circle in standard form is "#

#color(red)(bar(ul(|color(white)(2/2)color(black)((x-a)^2+(y-b)^2=r^2)color(white)(2/2)|)))#

#"where "(a,b)" are the coordinates of the centre and r is"#
#"the radius"#

#(x+6)^2+(y-15)^2=9" is in standard form"#

#"with "(a,b)=(-6,15)" and "r^2=9rArrr=3#

#rArr"centre "=(-6,15)#

#"and diameter "=2r=2xx3=6#