# How do you find the center, vertices, foci, and asymptotes of the hyperbola, and sketch its graph of #x^2/9 - y^2/16 = 1#?

##### 1 Answer

Mar 4, 2017

The center is

The vertices are (-3,0)

The foci are

The asymptotes are

#### Explanation:

We compare this equation

to

The center is

The vertices are

To find the foci, we need the distance from the center to the foci

The foci are

The asymptotes are

graph{((x^2)/9-(y^2)/16-1)(y-4/3x)(y+4/3x)=0 [-16.02, 16.02, -8.01, 8.01]}