# How do you find the critical points to graph  y=2cosx?

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Feb 9, 2018

The critical points are $0$, $\pi$, $2 \pi$, $- \pi$ and $- 2 \pi$.

#### Explanation:

Let $y = 2 \cos x$
Then the critical point(s) can be achieved by differentiating $y$ and equating it to $0$:

$\frac{\mathrm{dy}}{\mathrm{dx}} = 0$

$\frac{d}{\mathrm{dx}} 2 \cos x = 0$

$- 2 \sin x = 0$

$\sin x = 0$

$x = 0 , \pi , 2 \pi , - \pi$ and $- 2 \pi$.

These are the critical points

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