How do you find the critical points to graph # y=2cosx#?

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Feb 9, 2018

Answer:

The critical points are #0#, #pi#, #2pi#, #-pi# and #-2pi#.

Explanation:

Let #y = 2 cos x#
Then the critical point(s) can be achieved by differentiating #y# and equating it to #0#:

#dy/dx = 0#

#d/dx 2cosx= 0#

#-2 sin x = 0#

#sin x = 0#

#x=0,pi,2pi,-pi# and #-2pi#.

These are the critical points

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