Question

How do you find the definite integral for: `(6x+3)dx` for the intervals `[3, 9]`?

Answer 1

234

Explanation:

`int_3^9(6x+3)dx=[3x^2+3x]_3^9`
`=[3(9)^2+3(9)]-[3(3)^2+3(3)]`
`=270-36=234`