# How do you find the degree and leading coefficient of the polynomial 14y+30+y^2?

Jul 7, 2017

The degree is $2$, and the leading coefficient is $1$.

#### Explanation:

First, determine the degrees of each term:

$14 {y}^{1} + 30 {y}^{0} + {y}^{2}$

To write the polynomial in standard form, arrange the polynomial so that the degrees are in order from greatest to least.

${y}^{2} + 14 {y}^{1} + 30 {y}^{0}$
$= {y}^{2} + 14 y + 30$

The degree of the entire polynomial is equal to the degree of the first term. The leading coefficient is equal to the coefficient of the first term. Thus, the degree is $2$, and the leading coefficient is $1$.