# How do you find the degree, leading term, the leading coefficient, the constant term and the end behavior of p(t)=-t^2(3-5t)(t^2+t+4)?

If we multiply all of the parts together, we can see that the highest order term will be when we multiply the $- {t}^{2}$ with the $- 5 t$ and the ${t}^{2}$, so it will be a term that looks like $5 {t}^{5}$. That gives us the degree (5 in the exponent), the leading term ($5 {t}^{5}$), the leading coefficient (5) and the end behavior (more about that in a second). The constant term will be 0 because every term gets multiplied by ${t}^{2}$ so there is no constant term.
The end behavior for a polynomial is always the leading term. For very high values of $t$, the $5 {t}^{5}$ will be much larger than any of the other terms.