# How do you find the derivative of  1/[16x+3]^2 using the chain rule?

$f ' \left(x\right) = - \frac{32}{16 x + 3} ^ 3$
$f ' \left(x\right) = {\left(16 x + 3\right)}^{-} 2$
f'(x)=-2(16x+3)^-3*stackrel"This term = 16."overbrace(d/dx[16x+3]
$f ' \left(x\right) = - \frac{32}{16 x + 3} ^ 3$