How do you find the derivative of #1 / ln(x)#?

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heptadd Share
Jul 18, 2016

Answer:

# -1/(x(lnx)^2)#

Explanation:

#y = 1/lnx# , let #u = lnx#

#y = 1/u #
#dy/(du) = -1/u^2#

#(du)/dx * dy/(du) = -1/u^2 * (du)/dx#

#dy/dx = -1/(lnx)^2 * 1/x#
#dy/dx = -1/(x(lnx)^2)#

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