# How do you find the derivative of  1/t^2?

Aug 30, 2016

$\frac{\mathrm{dy}}{\mathrm{dx}} = - \frac{2}{t} ^ 3$

#### Explanation:

Given -

$y = \frac{1}{t} ^ 2$

It can be written as -

$y = {t}^{-} 2$

Then apply the differentiation rule to differentiate

$\frac{\mathrm{dy}}{\mathrm{dx}} = - 2 {t}^{-} 3$

This can be written as -

$\frac{\mathrm{dy}}{\mathrm{dx}} = - \frac{2}{t} ^ 3$