How do you find the derivative of #(2t)^5#?

Question

1873 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-03-03T02:45:03

#d/dt[(2t)^5]=160t^4#

Take out the constant and apply the power rule:

The power rule states: #d/dt[t^n]=nt^(n-1)#

So:

#d/dt[(2t)^5]<=>2^5*d/dt[t^5]#

#=2^5*color(red)5t^(color(red)(5-1))#

#=2^5*5t^4#

#=160t^4#