# How do you find the derivative of 2x^2+x-1?

Apr 13, 2017

$\frac{\mathrm{dy}}{\mathrm{dx}} \left(2 {x}^{2} + x - 1\right) = 4 x + 1$

#### Explanation:

Use the power rule $r {\left(a\right)}^{r - 1}$ and recall that the derivative of a constant is $0$

Therefore the derivative is,

$\frac{\mathrm{dy}}{\mathrm{dx}} = 2 \cdot 2 {x}^{2 - 1} + 1 {x}^{1 - 0} - 0$

$\frac{\mathrm{dy}}{\mathrm{dx}} = 4 x + 1$