# How do you find the derivative of 3/2 t^(1/2)?

$\frac{3 \sqrt{t}}{4 t}$
$y ' = \frac{3}{2} \cdot \frac{1}{2} \cdot {t}^{\frac{1}{2} - 1} = \frac{3}{4} {t}^{- \frac{1}{2}} = \frac{3}{4 {t}^{\frac{1}{2}}} = \frac{3}{4 \sqrt{t}} \cdot \frac{\sqrt{t}}{\sqrt{t}} = \frac{3 \sqrt{t}}{4 t}$