Question

How do you find the derivative of `[(4x ^ 2 + 7) ^2 (2x^3 + 1)^4]`?

Answer 1

`24x^2(4x^2+7)^2(2x^3+1)^3+16x(2x^3+1)^4(4x^2+7)`

Explanation:

Using the product rule, which will contain 2 power rules, we get :

`(df)/dx=(4x^2+7)^2*4(2x^3+1)^3*6x^2+(2x^3+1)^4*2(4x^2+7)*8x`