# How do you find the derivative of 6/(x^2 + 3)?

Jun 20, 2016

$\frac{- 12 x}{{x}^{2} + 3} ^ 2$

#### Explanation:

By the definition of the quotient rule,
$\frac{\left({x}^{2} + 3\right) \cdot 6 ' - 6 \left(2 x\right)}{{x}^{2} + 3} ^ 2$

We know that the derivative of any integer is zero. So 6' would be zero.

Therefore, the derivative would be

$\frac{- 12 x}{{x}^{2} + 3} ^ 2$