Question

How do you find the derivative of `(6x^5 + 3x^3 +x)/x^2`?

Answer 1

`d/dx(6x^5+3x^3+x)/x^2=((x^2)(30x^4+9x^2+1)-2x(6x^5+3x^3+x))/x^4`

Explanation:

We may use the quotient rule to differentiate this function to obtain :

`d/dx(6x^5+3x^3+x)/x^2=((x^2)(30x^4+9x^2+1)-2x(6x^5+3x^3+x))/x^4`