How do you find the derivative of #8x^2+9x+12#?

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Answer 1 · 2018-04-14T12:56:21

#d/dx[8x^2+9x+12]=16x+9#

Remember that:

#d/dx[x^n]=nx^(n-1)# if #n# is a constant.

Therefore, the derivative is:

#8*2x^(2-1)+9*1*x^(1-1)+12*0*x^(0-1)#

#=>16x^(1)+9x^(0)+0#

#=>16x+9#

That is the answer!

Answer 2 · 2018-04-14T13:44:33

#16x+9#

#"differentiate each term using the "color(blue)"power rule"#

#•color(white)(x)d/dx(ax^n)=nax^(n-1)#

#rArrd/dx(8x^2+9x+12)=16x+9#