# How do you find the derivative of: arcsin x + arccos x?

May 14, 2015

Since the derivative of

$y = \arcsin x$

is

$y ' = \frac{1}{\sqrt{1 - {x}^{2}}}$

and the derivative of

$y = \arccos x$

is

$y ' = - \frac{1}{\sqrt{1 - {x}^{2}}}$,

The derivative of the function is $0$.