Question

How do you find the derivative of `f(x)=2/3x^3-x^2-24x-4`?

Answer 1

By the power rule:

`f'(x) =3 xx 2/3x^(3 - 1) - 1 xx 2x^(2 - 1) - 1 xx 24x^(1 - 1) - 0 xx 4x^(0 - 1)`

`f'(x) = 2x^2 - 2x - 2`

Hopefully this helps!