How do you find the derivative of # f (x) = ln(1 - sin x)#?
1 Answer
Explanation:
Differentiate using the
#color(blue)" chain rule " #
# d/dx [ f(g(x)) ] = f'(g(x)) . g'(x) # and
# d/dx(lnx) = 1/x #
# rArr f'(x) = 1/(1 - sinx) . d/dx( 1 - sinx) = - cosx/(1 - sinx)=cosx/(sinx-1)#
