How do you find the derivative of #f(x)=ln (x^2+2)#? Calculus Basic Differentiation Rules Chain Rule 1 Answer Rhys May 7, 2018 #(2x)/(x^2 + 2 ) # Explanation: Chain rule: #d/dx f(g(x) ) = f'(g(x)) g'(x) # #=> d/dx ln f(x) =( f'(x))/f(x) # #=> d/dx ln(x^2 + 2) = (d/dx(x^2+2)) / (x^2 + 2) # # therefore = (2x)/(x^2 + 2 ) # Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 1714 views around the world You can reuse this answer Creative Commons License