How do you find the derivative of #f(x) = x^3 + 6x^2#? Calculus Basic Differentiation Rules Power Rule 1 Answer tcw1 Sep 11, 2016 #3x^2+12x# Explanation: #d/dxx^3+6x^2# Exponent rule: #d/dx x^n= nx^(n-1)# #3x^(3-1)+(6)2x^(2-1)# #3x^2+12x# Answer link Related questions How do you find the derivative of a polynomial? How do you find the derivative of #y =1/sqrt(x)#? How do you find the derivative of #y =4/sqrt(x)#? How do you find the derivative of #y =sqrt(2x)#? How do you find the derivative of #y =sqrt(3x)#? How do you find the derivative of #y =sqrt(x)#? How do you find the derivative of #y =sqrt(x)# using the definition of derivative? How do you find the derivative of #y =sqrt(3x+1)#? How do you find the derivative of #y =sqrt(9-x)#? How do you find the derivative of #y =sqrt(x-1)#? See all questions in Power Rule Impact of this question 1735 views around the world You can reuse this answer Creative Commons License