Question

How do you find the derivative of `g(x)=3(2-5x)^6`?

Answer 1

`g'(x) = -90(2-5x)^5`

Explanation:

Use the differentiation power rule `(u^n)' = n u^(n-1) u'`
Note: `d/(du) (3u) = 3`

Let `u = 2-5x, u' = -5`

`g'(x) = 3*6(2-5x)^5 (-5)`

`g'(x) = -90(2-5x)^5`