Question

How do you find the derivative of `h(s)=s^(4/5)-s^(2/3)`?

Answer 1

`h'(s) = 4/(5 root(5)s) - 2/(3 root(3) s)`

Explanation:

`h(s)=s^(4/5)-s^(2/3)`

`h'(s) = 4/5 s^((4/5-1)) - 2/3 s^((2/3-1))`

`h'(s) = 4/5 s^((-1/5)) - 2/3 s^((-1/3))`

`h'(s) = 4/(5 s^((1/5))) - 2/(3 s^((1/3))`

`h'(s) = 4/(5 root(5)s) - 2/(3 root(3) s)`