Question

How do you find the derivative of `R(w)=w^3*cos(4w)`?

Answer 1

`R'(w) = w^2(3cos4w - 4wsin4w)`

Explanation:

`R'(w) = (w^3)'cos4w + w^3 (cos4w)'`

`R'(w) = 3w^2cos4w - 4w^3sin4w`

`R'(w) = w^2(3cos4w - 4wsin4w)`