How do you find the derivative of #r(x)= (0.3x^2-4.2x+9.2)^1.5#? Calculus Basic Differentiation Rules Chain Rule 1 Answer Sasha P. Mar 15, 2016 #r'(x)= (0.9x-6.3)sqrt(0.3x^2-4.2x+9.2)# Explanation: #r(x)= (0.3x^2-4.2x+9.2)^1.5# #r(x)= (0.3x^2-4.2x+9.2)^(3/2)# #r'(x)= 3/2(0.3x^2-4.2x+9.2)^(1/2) * (0.3x^2-4.2x+9.2)'# #r'(x)= 3/2(0.3x^2-4.2x+9.2)^(1/2) * (0.6x-4.2)# #r'(x)= (0.9x-6.3)sqrt(0.3x^2-4.2x+9.2)# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 1500 views around the world You can reuse this answer Creative Commons License