Question

How do you find the derivative of `sin(2x+1)`?

Answer 1

Use the chain rule.

Explanation:

Say if the problem `y=sin(ax+b)`
Then you can find the derivative of this using chain rule.

`dy/dx = cos(ax+b)*d/dx(ax+b)`
`dy/dx = cos(ax+b)(a)`
`dy/dx = acos(ax+b)`

Similarly

`y=sin(2x+1)`
`dy/dx = cos(2x+1)d/dx(2x+1)`
`dy/dx = cos(2x+1)(2)`

`dy/dx=2cos(2x+1)` Answer