# How do you find the derivative of sqrt(1/x^3)?

First write the function as ${x}^{-} \left(\frac{3}{2}\right)$
As we know (x^a")'=ax^(a-1):
Then ${x}^{-} \left(\frac{3}{2}\right) ' = - \frac{3}{2} {x}^{- \frac{5}{2}}$
or $- \frac{3}{2 \sqrt{{x}^{5}}}$