# How do you find the derivative of sqrt(2x-3)?

Apr 18, 2018

$f ' \left(x\right) = \frac{1}{\sqrt{2 x - 3}}$

#### Explanation:

$f \left(x\right) = \sqrt{2 x - 3}$

$f ' \left(x\right) = \frac{1}{2 \sqrt{2 x - 3}} \cdot 2$

$f ' \left(x\right) = \frac{1}{\cancel{2} \sqrt{2 x - 3}} \cdot \cancel{2}$

$f ' \left(x\right) = \frac{1}{\sqrt{2 x - 3}}$