How do you find the derivative of #sqrt(5x)#? Calculus Basic Differentiation Rules Chain Rule 1 Answer Topscooter Dec 20, 2015 If #u# is a function, then the derivative of #u^n# is #n*u'*u^(n-1)#. We apply this here. #f(x) = sqrt(5x) = (5x)^(1/2)# so #f'(x) = 1/2*5*(5x)^(1/2 - 1) = 5/(2sqrt(5x))#. Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 1619 views around the world You can reuse this answer Creative Commons License