# How do you find the derivative of sqrt(x^2+2x-1)?

$\frac{d}{\mathrm{dx}} {\left({x}^{2} + 2 x - 1\right)}^{\frac{1}{2}} = \frac{1}{2} {\left({x}^{2} + 2 x - 1\right)}^{- \frac{1}{2}} \cdot \left(2 x + 2\right)$
$\frac{d}{\mathrm{dx}} {\left({x}^{2} + 2 x - 1\right)}^{\frac{1}{2}} = \frac{1}{2} {\left({x}^{2} + 2 x - 1\right)}^{- \frac{1}{2}} \cdot \left(2 x + 2\right)$