# How do you find the derivative of the function f(x)=arcsin(4x)+arccos(4x)?

May 14, 2015

Since the derivative of

$y = \arcsin 4 x$

is

$y ' = \frac{1}{\sqrt{1 - 16 {x}^{2}}} \cdot 4$

and the derivative of

$y = \arccos 4 x$

is

$y ' = - \frac{1}{\sqrt{1 - 16 {x}^{2}}} \cdot 4$,

The derivative of the function is $0$.