How do you find the derivative of #y=2(5x+3)^7-1# using the chain rule? Calculus Basic Differentiation Rules Chain Rule 1 Answer Jim G. · mason m Feb 4, 2016 Answer: # dy/dx = 70(5x+3)^6 # Explanation: Note: derivative of a constant is zero so #d/dx(-1) = 0 # differentiate using the # color(blue)(" chain rule") # # dy/dx = 7*2(5x+3)^6 d/dx (5x+3) =14(5x+3) * 5 # # rArr dy/dx = 70(5x+3)^6# Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 209 views around the world You can reuse this answer Creative Commons License