How do you find the derivative of #y=4x^(-1/4)-5+sqrt(3x)#? Calculus Basic Differentiation Rules Power Rule 1 Answer Sasha P. Oct 17, 2015 #y'=-x^(-5/4)+3/(2sqrt(3x))# Explanation: #y'=4(-1/4)x^(-1/4-1)+1/(2sqrt(3x))*(3x)'# #y'=-x^(-5/4)+3/(2sqrt(3x))# Answer link Related questions How do you find the derivative of a polynomial? How do you find the derivative of #y =1/sqrt(x)#? How do you find the derivative of #y =4/sqrt(x)#? How do you find the derivative of #y =sqrt(2x)#? How do you find the derivative of #y =sqrt(3x)#? How do you find the derivative of #y =sqrt(x)#? How do you find the derivative of #y =sqrt(x)# using the definition of derivative? How do you find the derivative of #y =sqrt(3x+1)#? How do you find the derivative of #y =sqrt(9-x)#? How do you find the derivative of #y =sqrt(x-1)#? See all questions in Power Rule Impact of this question 1568 views around the world You can reuse this answer Creative Commons License