# How do you find the derivative of y=4x^(-1/4)-5+sqrt(3x)?

$y ' = - {x}^{- \frac{5}{4}} + \frac{3}{2 \sqrt{3 x}}$
$y ' = 4 \left(- \frac{1}{4}\right) {x}^{- \frac{1}{4} - 1} + \frac{1}{2 \sqrt{3 x}} \cdot \left(3 x\right) '$
$y ' = - {x}^{- \frac{5}{4}} + \frac{3}{2 \sqrt{3 x}}$