# How do you find the derivative of #y = arctan(x^2)#?

##### 1 Answer

Mar 16, 2016

#### Explanation:

Using the

#color(blue)" chain rule " #

#d/dx [ f(g(x)) ] = f'(g(x)) . g'(x) # and the standard derivative

#d/dx(tan^-1 x) = 1/(1 + x^2) #

#rArr dy/dx = 1/(1 + (x^2)^2) .d/dx (x^2) = (2x)/(1 + x^4) #