How do you find the derivative of #y=e^(2x^3)#? Calculus Differentiating Logarithmic Functions Differentiating Logarithmic Functions with Base e 1 Answer Henry W. Oct 12, 2016 #(dy)/(dx)=6x^2e^(2x^3)# Explanation: Use the chain rule: #(dy)/(dx)=(dy)/(du)*(du)/(dx)# #y=e^(2x^3),# let #u=2x^3# #(dy)/(du)=e^u=e^(2x^3), (du)/(dx)=6x^2# So #(dy)/(dx)=e^(2x^3)*6x^2=6x^2e^(2x^3)# Answer link Related questions What is the derivative of #f(x)=ln(g(x))# ? What is the derivative of #f(x)=ln(x^2+x)# ? What is the derivative of #f(x)=ln(e^x+3)# ? What is the derivative of #f(x)=x*ln(x)# ? What is the derivative of #f(x)=e^(4x)*ln(1-x)# ? What is the derivative of #f(x)=ln(x)/x# ? What is the derivative of #f(x)=ln(cos(x))# ? What is the derivative of #f(x)=ln(tan(x))# ? What is the derivative of #f(x)=sqrt(1+ln(x)# ? What is the derivative of #f(x)=(ln(x))^2# ? See all questions in Differentiating Logarithmic Functions with Base e Impact of this question 10777 views around the world You can reuse this answer Creative Commons License