How do you find the derivative of #y=pi/2sintheta-costheta#?
1 Answer
Jun 19, 2017
Explanation:
#"note that " pi/2" is a constant"#
#"using "color(blue)"standard derivatives"#
#• d/dx(sinx)=cosx" and " d/dx(cosx)=-sinx#
#rArrdy/dx=pi/2cosx+sinx#
