Question

How do you find the derivative of `y= root3(e^x+1)` ?

Answer 1

`y'=1/3(e^x+1)^(-2/3)*e^x`

Explanation :

`y=(e^x+1)^(1/3)`

let's `y=(f(x))^(1/3)`, then from Chain Rule,

`y'=1/3(f(x))^(-2/3)f'(x)`

Similarly following for the give problem and using Chain Rule, yields

`y'=1/3(e^x+1)^(-2/3)*e^x`