How do you find the derivative of #y=(x^2+5)^2#? Calculus Basic Differentiation Rules Chain Rule 1 Answer marfre Mar 1, 2017 #y' = 4x(x^2 + 5)# Explanation: Use the chain rule and the power rule: #(u^n)' = n u^(n-1) u'# #y' = 2(x^2 + 5)^1 (2x)# #y' = 4x(x^2 + 5)# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 4198 views around the world You can reuse this answer Creative Commons License