How do you find the discriminant and how many solutions does #x^2+2x+7=0# have?

1 Answer
Apr 30, 2015

The equation is of the form #color(blue)(ax^2+bx+c=0# where:

#a=1, b=2, c=7#

The Disciminant is given by :
#Delta=b^2-4*a*c#
# = (2)^2-4*1*7#
# = 4-28=-24#

If #Delta=0# then there is only one solution.
(for #Delta>0# there are two solutions,
for #Delta<0# there are no real solutions)

As #Delta < 0#, this equation has NO REAL SOLUTIONS

  • Note:
    The solutions are normally found using the formula
    #x=(-b+-sqrtDelta)/(2*a)#