How do you find the discriminant for #2.25x^2-3x=-1# and determine the number and type of solutions?

1 Answer
Apr 16, 2018

Answer:

#color(violet)(b^2 - 4ac = 0, " Given equation has one real repeated root " -(2/3)#

Explanation:

https://newcollegeswindonmaths.wordpress.com/2016/04/10/core-1-discriminant/

#2.25x^2 - 3x + 1 = 0#

#a = 2.25, b = -3, c = 1#

#D = b^2 - 4ac = (-3)^2 - (4 * 2.25 * 1) = 9 - 9 = 0#

Since #color(violet)(b^2 - 4ac = 0, " Given equation has one real repeated root "#

#"and the root is " = b / (2a) = -3 / (2 * 2.25) = -3/4.5 = -2/3#