How do you find the discriminant for #y=x^2-6x+9#?
1 Answer
Mar 5, 2018
Explanation:
#"for a quadratic in standard form"#
#•color(white)(x)y=ax^2+bx+c color(white)(x)a!=0#
#"the "color(blue)"discriminant"# is.
#•color(white)(x)Delta=b^2-4ac#
#y=x^2-6x+9larrcolor(blue)"is in standard form"#
#"with "a=1,b=-6" and "c=9#
#rArrDelta=(-6)^2-(4xx1xx9)=36-36=0#
