# How do you find the discriminant of 4x^2 +12x+9=0?

Dec 13, 2016

See explanation.

#### Explanation:

For a quadratic equation $a {x}^{2} + b x + c = 0$ the discriminant is defined as:

## $\Delta = {b}^{2} - 4 \cdot a \cdot c$ 

In the given equation we have:

$a = 4$, $b = 12$ and $c = 9$, so:

$\Delta = {12}^{2} - 4 \cdot 4 \cdot 9 = 144 - 144 = 0$